设多项式为ax3 + bx2 + cx + d，零为α，β和γ
然后，α+β+γ=-（-2）/ 1 = 2 = -b / aαβ+βγ+γα= -7 = -7/1 = c / aαβγ= -14 = -14/1 =- d / a
∴a = 1，b = -2，c = -7，d = 14
因此，一个满足给定条件的三次多项式将为x3 – 2×2 – 7x + 14
更新:20210423 104156
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发布时间：2020-09-13 13:27:54 作者：冬青好
设多项式为ax3 + bx2 + cx + d，零为α，β和γ
然后，α+β+γ=-（-2）/ 1 = 2 = -b / aαβ+βγ+γα= -7 = -7/1 = c / aαβγ= -14 = -14/1 =- d / a
∴a = 1，b = -2，c = -7，d = 14
因此，一个满足给定条件的三次多项式将为x3 – 2×2 – 7x + 14
更新:20210423 104156.
